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(x/(x-1))+(1/(x-2))=(2x^2-3)/(x^2-3x+2)
We move all terms to the left:
(x/(x-1))+(1/(x-2))-((2x^2-3)/(x^2-3x+2))=0
Domain of the equation: (x-1))!=0
x∈R
Domain of the equation: (x-2))!=0
x∈R
Domain of the equation: (x^2-3x+2))!=0We calculate fractions
x∈R
((-3x+x*(x-2))*x^2)/((x-1))*(x-2))*(x^2-3x+2)))+((-3x+1*(x-1))*x^2)/((x-1))*(x-2))*(x^2-3x+2)))+(-((2x^2-3)*(x-1))*x)/((x-1))*(x-2))*(x^2-3x+2)))=0
We can not solve this equation
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